初一 数学 因式分解的简单应用 请详细解答,谢谢! (21 18:50:51)

发布网友 发布时间:2024-10-24 02:38

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热心网友 时间:2024-11-17 23:06

1. (x2+2xy+y2)/(x+y) =(x+y)^2/(x+y)=x+y

2. [(a-b)2+2(b-a)]/(a-b) = (a-b)-2

3. (ab2+a2b)/(a+b)=ab(b+a)/(a+b)=ab

4. (x2-49)/(7-x) =(x-7)(x+7)/(7-x)=-(x+7)

5. (4mn3+6m3n)/(2n2+3m2)=2mn(2n^2+3m^2)/(2n^2+3m^2)=2mn

6. [(2a-1)2-(3a-1)2]/(5a-2)=[(2a-1+3a-1)(2a-1-3a+1)]/(5a-2)=-a

热心网友 时间:2024-11-17 23:06

1.
(x^2+2xy+y^2)/(x+y)
=(x+y)^2/(x+y)
=x+y

2.
[(a-b)^2+2(b-a)]/(a-b)
=[(a-b)^2-2(a-b)]/(a-b)
=(a-b)[(a-b)-2]/(a-b)
=(a-b)-2
=a-b-2

3.
(ab^2+a^2b)/(a+b)
=ab(b+a)/(a+b)
=ab

4.
(x^2-49)/(7-x)
=[(x-7)(x+7)]/(7-x)
=[(x-7)(x+7)]/[-(x-7)]
=-(x+7)
=-x-7

5.
(4mn^3+6m^3n)/(2n^2+3m^2)
=mn(4n^2+6m^2)/(2n^2+3m^2)
=2mn(2n^2+3m^2)/(2n^2+3m^2)
=2mn

6.
[(2a-1)^2-(3a-1)^2]/(5a-2)
=[(2a-1)-(3a-1)][(2a-1)+(3a-1)]/(5a-2)
=[(2a-1-3a+1)(2a-1+3a-1)]/(5a-2)
=[(-a)(5a-2)]/(5a-2)
=-a

热心网友 时间:2024-11-17 23:07

1. (x2+2xy+y2)/(x+y)=(x+y)²/(x+y)=x+y
=
2. [(a-b)2+2(b-a)]/(a-b)=[(a-b)(a-b-2)] /(a-b)=a-b-2

3. (ab2+a2b)/(a+b)=ab(b+a)/(a+b)=ab

4. (x2-49)/7-x)=(x+7)(x-7)/(7-x)=-x-7

5. (4mn3+6m3n)/(2n2+3m2)=2mn(2n²+3m²)/(2n²+3m²)=2mn

6. [(2a-1)2-(3a-1)2]/(5a-2)=[(2a-1+3a-1)(2a-1-3a+1)]/(5a-2)
=(5a-2)(-a)(5a-2)=-a

热心网友 时间:2024-11-17 23:07

1. (x2+2xy+y2)/(x+y)=(x+y)²/(x+y)=x+y

2. [(a-b)2+2(b-a)]/(a-b)=[(a-b)²-2(a-b)]/(a-b)=[(a-b)-2]=a-b-2

3. (ab2+a2b)/(a+b)=[ab(b+a)]/(a+b)=ab

4. (x2-49)/7-x)=[(x+7)(x-7)]/(7-x)=-(x+7)=-x-7

5. (4mn3+6m3n)/(2n2+3m2) =[2mn(2n²+3m²)]/(2n²+3m²)=2mn

6. [(2a-1)2-(3a-1)2]/(5a-2)=[(2a-1+3a-1)(2a-1-3a+1)]/(5a-2)=[(5a-2)(-a)]/(5a-2)=-a

热心网友 时间:2024-11-17 23:08

1.(x2+2xy+y2)/(x+y) =(x+y)2/(x+y)=x+y
2.[(a-b)2+2(b-a)]/(a-b) =(a-b)*(a-b-2)/(a-b)=a-b-2
3.(ab2+a2b)/(a+b)=ab*(a+b)/(a+b)=ab
4.(x2-49)/(7-x)=(x+7)*(x-7)/(7-x)=-(x+7)
5.(4mn3+6m3n)/(2n2+3m2) =2mn*(2n2+3m2)/(2n2+3m2)=2mn
6.[(2a-1)2-(3a-1)2]/(5a-2)=(5a-2)*(-a)/(5a-2)=-a

热心网友 时间:2024-11-17 23:09

1.(x+y)(X+Y)÷(X+Y)=x+y
2.[(a-b)2+2(b-a)]/(a-b)=[(a-b)(a-b-2)] /(a-b)=a-b-2
3.[ab(a+b)]/(a+b)=ab
4.(x-7)(x+7)/(7-x)=-(x+7)
5.2mn(2n2+3m2)/(2n2+3m2)=2mn
6.平方差展开(2a-1-3a+1)(2a-1+3a-1)/(5a-2)=-a

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